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Quiz Chapter 4: Indices, Surds and Logarithms

10 questions · Form 4 Additional Mathematics Bab 4: Indices, Surds and Logarithms

Question 1 of 10Score: 0

Rationalise the denominator of 6 / √3.

Full Question List & Answer Key

Prefer reading to quizzing? All 10 questions are listed below with the answer and explanation under each one.

1. Rationalise the denominator of 6 / √3.

  1. 2√3
  2. 3√3
  3. 6√3
  4. √3
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Answer: A

Multiply numerator and denominator by √3: 6 × √3√3 × √3 = 6√33 = 2√3.

2. Simplify √20 + √45 - √5.

  1. 4√5
  2. 5√5
  3. 3√5
  4. 2√5
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Answer: A

Simplify each surd: √20 = 2√5, √45 = 3√5. Then 2√5 + 3√5 - 1√5 = (2 + 3 - 1)√5 = 4√5.

3. If 3^(x + 2) = 27^(x - 1), find the value of x.

  1. x = 52
  2. x = 32
  3. x = 2
  4. x = 3
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Answer: A

Express base as 3: 3^(x + 2) = (3³)^(x - 1) => 3^(x + 2) = 33x - 3) => x + 2 = 3x - 3 => 2x = 5 => x = 52.

4. Simplify the surd √72 into its simplest form a√b.

  1. 3√8
  2. 2√18
  3. 6√2
  4. 36√2
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Answer: C

Find the largest perfect square factor: √72 = √(36 × 2) = √36 × √2 = 6√2.

5. Solve 5^x = 20 correct to 3 decimal places.

  1. 1.861
  2. 1.301
  3. 2.000
  4. 1.431
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Answer: A

Take log₁₀ on both sides: log₁₀ (5^x) = log₁₀ 20 => x log₁₀ 5 = log₁₀ 20 => x = log₁₀ 20 / log₁₀ 5 ≈ 1.301030.69897 ≈ 1.861.

6. Which of the following numbers is an example of a surd?

  1. √16
  2. 94
  3. √7
  4. ∛27
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Answer: C

√16 = 4, √(94) = 32, and ∛27 = 3 are all rational numbers. √7 is irrational and cannot be expressed as a ratio of integers, making it a surd.

7. Simplify (3√2 + √5)(3√2 - √5).

  1. 13
  2. 18
  3. 23
  4. 13 + 6√10
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Answer: A

Use difference of squares (a + b)(a - b) = a² - b²: (3√2)² - (√5)² = (9 × 2) - 5 = 18 - 5 = 13.

8. Convert the logarithmic equation log₃ 81 = 4 into index form.

  1. 4³ = 81
  2. 3⁴ = 81
  3. 811/4) = 3
  4. 3⁸¹ = 4
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Answer: B

Using log_a N = x <=> a^x = N, log₃ 81 = 4 converts directly to 3⁴ = 81.

9. Given log₁₀ 2 = p and log₁₀ 3 = q, express log₁₀ 18 in terms of p and q.

  1. p + 2q
  2. 2p + q
  3. p + q²
  4. 6pq
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Answer: A

18 = 2 × 3² = 2 × 9. log₁₀ (2 × 3²) = log₁₀ 2 + log₁₀ (3²) = log₁₀ 2 + 2 log₁₀ 3 = p + 2q.

10. What is the value of log_x x - log_x 1?

  1. 1
  2. 0
  3. x
  4. Undefined
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Answer: A

Since log_x x = 1 and log_x 1 = 0, we have 1 - 0 = 1.

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